Posted by
Soltys, 17-05-2007 15:56
#!/usr/bin/python
a = 3
b = 7
c = 8
wynik = 808
pp = 0
n = 0
while (pp <= wynik):
pp = 2*a*n*b*n + 2*b*n*c*n + 2*a*n*c*n
n += 0.1
n -= 0.1 # Pętla while robi jedną nadmiarową pętlę
print pp
print n
a = a*n
b = b*n
c = c*n
print "A = %s, B = %s, C = %s" %(a,b,c)
print "A n wynosi %d" %n
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